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Feature #5553
closedРеализовать правило (AND (NOT (EQ expr const1)) (EQ expr const2)) => (EQ expr const2), если const2 != const1
Start date:
01/13/2015
Due date:
% Done:
100%
Estimated time:
Published in build:
Description
expr - выражение.
const1, const2 - константы.
Updated by Artem Kotsynyak about 9 years ago
- Status changed from New to Feedback
- % Done changed from 0 to 100
r780 needs review, may introduce regressions in client code.
Updated by Alexander Kamkin about 9 years ago
- Subject changed from [transformer][ruleset] реализовать правило (AND (NOT (EQ expr const1)) (EQ expr const2)) => (EQ expr const2), если const2 != const1 to Реализовать правило (AND (NOT (EQ expr const1)) (EQ expr const2)) => (EQ expr const2), если const2 != const1
- Category set to Transformer
Updated by Artem Kotsynyak about 9 years ago
- Status changed from Feedback to Resolved
Mark the issue as resolved due to lack of negative feedback.
Updated by Igor Melnichenko almost 9 years ago
- Status changed from Resolved to Verified
Updated by Artem Kotsynyak almost 9 years ago
- Status changed from Verified to Closed
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